-16t2+1600=0

Solution for -16t2+1600=0 equation:

-16t^2+1600=0

a = -16; b = 0; c = +1600;
Δ = b2-4ac
Δ = 02-4·(-16)·1600
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{102400}=320$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-320}{2*-16}=\frac{-320}{-32}
=+10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+320}{2*-16}=\frac{320}{-32}
=-10
$