-16t2+1700=930

Solution for -16t2+1700=930 equation:

-16t^2+1700=930

We move all terms to the left:

-16t^2+1700-(930)=0

We add all the numbers together, and all the variables

-16t^2+770=0

a = -16; b = 0; c = +770;
Δ = b2-4ac
Δ = 02-4·(-16)·770
Δ = 49280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{49280}=\sqrt{64*770}=\sqrt{64}*\sqrt{770}=8\sqrt{770}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{770}}{2*-16}=\frac{0-8\sqrt{770}}{-32}
=-\frac{8\sqrt{770}}{-32}
=-\frac{\sqrt{770}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{770}}{2*-16}=\frac{0+8\sqrt{770}}{-32}
=\frac{8\sqrt{770}}{-32}
=\frac{\sqrt{770}}{-4}
$