-16t2+32t+377.3=0

Solution for -16t2+32t+377.3=0 equation:

-16t^2+32t+377.3=0

a = -16; b = 32; c = +377.3;
Δ = b2-4ac
Δ = 322-4·(-16)·377.3
Δ = 25171.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-\sqrt{25171.2}}{2*-16}=\frac{-32-\sqrt{25171.2}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+\sqrt{25171.2}}{2*-16}=\frac{-32+\sqrt{25171.2}}{-32}
$