-16x2+0,1224x=0

Solution for -16x2+0,1224x=0 equation:

-16x^2+0.1224x=0

a = -16; b = 0.1224; c = 0;
Δ = b2-4ac
Δ = 0.12242-4·(-16)·0
Δ = 0.01498176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1224)-\sqrt{0.01498176}}{2*-16}=\frac{-0.1224-\sqrt{0.01498176}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1224)+\sqrt{0.01498176}}{2*-16}=\frac{-0.1224+\sqrt{0.01498176}}{-32}
$