-16x2+128x+96=0

Solution for -16x2+128x+96=0 equation:

-16x^2+128x+96=0

a = -16; b = 128; c = +96;
Δ = b2-4ac
Δ = 1282-4·(-16)·96
Δ = 22528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22528}=\sqrt{1024*22}=\sqrt{1024}*\sqrt{22}=32\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-32\sqrt{22}}{2*-16}=\frac{-128-32\sqrt{22}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+32\sqrt{22}}{2*-16}=\frac{-128+32\sqrt{22}}{-32}
$