-16x2+27x-10=0

Solution for -16x2+27x-10=0 equation:

-16x^2+27x-10=0

a = -16; b = 27; c = -10;
Δ = b2-4ac
Δ = 272-4·(-16)·(-10)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{89}}{2*-16}=\frac{-27-\sqrt{89}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{89}}{2*-16}=\frac{-27+\sqrt{89}}{-32}
$