-16x2+36=-48x

Solution for -16x2+36=-48x equation:

-16x^2+36=-48x

We move all terms to the left:

-16x^2+36-(-48x)=0

We get rid of parentheses

-16x^2+48x+36=0

a = -16; b = 48; c = +36;
Δ = b2-4ac
Δ = 482-4·(-16)·36
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48\sqrt{2}}{2*-16}=\frac{-48-48\sqrt{2}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48\sqrt{2}}{2*-16}=\frac{-48+48\sqrt{2}}{-32}
$