-16x2+64x+50=0

Solution for -16x2+64x+50=0 equation:

-16x^2+64x+50=0

a = -16; b = 64; c = +50;
Δ = b2-4ac
Δ = 642-4·(-16)·50
Δ = 7296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7296}=\sqrt{64*114}=\sqrt{64}*\sqrt{114}=8\sqrt{114}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-8\sqrt{114}}{2*-16}=\frac{-64-8\sqrt{114}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+8\sqrt{114}}{2*-16}=\frac{-64+8\sqrt{114}}{-32}
$