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-16x^2=112x
We move all terms to the left:
-16x^2-(112x)=0
a = -16; b = -112; c = 0;
Δ = b2-4ac
Δ = -1122-4·(-16)·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-112}{2*-16}=\frac{0}{-32} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+112}{2*-16}=\frac{224}{-32} =-7 $
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