-17(z+1)+6(4z-3)=6(z-5)+13

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Solution for -17(z+1)+6(4z-3)=6(z-5)+13 equation:


-17(z+1)+6(4z-3)=6(z-5)+13

We simplify the equation to the form, which is simple to understand 
-17(z+1)+6(4z-3)=6(z-5)+13

Reorder the terms in parentheses
+(-17z-17)+6*(4z-3)=6*(z-5)+13

Remove unnecessary parentheses
-17z-17+6+*(+4z-3+)=+6+*(+z-5+)+13

Reorder the terms in parentheses
-17z-17+(+24z-18)=6*(z-5)+13

Remove unnecessary parentheses
-17z-17+24z-18=+6+*(+z-5+)+13

Reorder the terms in parentheses
-17z-17+24z-18=+(+6z-30)+13

Remove unnecessary parentheses
-17z-17+24z-18=+6z-30+13

We move all terms containing z to the left and all other terms to the right. 
-17z+24z-6z=-30+13+17+18

We simplify left and right side of the equation. 
+1z=+18

We divide both sides of the equation by 1 to get z. 
z=18

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