-17(z+2)+6(4z-6)=6(z-4)+11

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Solution for -17(z+2)+6(4z-6)=6(z-4)+11 equation: 



-17(z+2)+6(4z-6)=6(z-4)+11

We move all terms to the left:

-17(z+2)+6(4z-6)-(6(z-4)+11)=0

We multiply parentheses

-17z+24z-(6(z-4)+11)-34-36=0



We calculate terms in parentheses: -(6(z-4)+11), so:

6(z-4)+11

We multiply parentheses

6z-24+11

We add all the numbers together, and all the variables

6z-13

Back to the equation:

-(6z-13)



We add all the numbers together, and all the variables

7z-(6z-13)-70=0

We get rid of parentheses

7z-6z+13-70=0

We add all the numbers together, and all the variables

z-57=0

We move all terms containing z to the left, all other terms to the right

z=57

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