-17=1/3(9y+12

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Solution for -17=1/3(9y+12 equation: 



-17=1/3(9y+12

We move all terms to the left:

-17-(1/3(9y+12)=0



Domain of the equation: 3(9y+12)-17!=0

We move all terms containing y to the left, all other terms to the right

3(9y+12)!=17

y∈R



We multiply all the terms by the denominator


-(1=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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