-17=1/3(9y+12)

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Solution for -17=1/3(9y+12) equation: 



-17=1/3(9y+12)

We move all terms to the left:

-17-(1/3(9y+12))=0



Domain of the equation: 3(9y+12))!=0

y∈R



We multiply all the terms by the denominator


-(1-17*3(9y+12))=0



We calculate terms in parentheses: -(1-17*3(9y+12)), so:

1-17*3(9y+12)

determiningTheFunctionDomain
-17*3(9y+12)+1

Wy multiply elements

-51y(9+1

Back to the equation:

-(-51y(9+1)



We add all the numbers together, and all the variables

-(-51y10=0

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