-18(3x-5)-23=4(-x+2)

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Solution for -18(3x-5)-23=4(-x+2) equation: 



-18(3x-5)-23=4(-x+2)

We move all terms to the left:

-18(3x-5)-23-(4(-x+2))=0

We add all the numbers together, and all the variables

-18(3x-5)-(4(-1x+2))-23=0

We multiply parentheses

-54x-(4(-1x+2))+90-23=0



We calculate terms in parentheses: -(4(-1x+2)), so:

4(-1x+2)

We multiply parentheses

-4x+8

Back to the equation:

-(-4x+8)



We add all the numbers together, and all the variables

-54x-(-4x+8)+67=0

We get rid of parentheses

-54x+4x-8+67=0

We add all the numbers together, and all the variables

-50x+59=0

We move all terms containing x to the left, all other terms to the right

-50x=-59

x=-59/-50

x=1+9/50

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