-18+3/8(16-40x)=8

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Solution for -18+3/8(16-40x)=8 equation: 



-18+3/8(16-40x)=8

We move all terms to the left:

-18+3/8(16-40x)-(8)=0



Domain of the equation: 8(16-40x)!=0

x∈R



We add all the numbers together, and all the variables

3/8(-40x+16)-18-8=0

We add all the numbers together, and all the variables

3/8(-40x+16)-26=0

We multiply all the terms by the denominator


-26*8(-40x+16)+3=0

Wy multiply elements

-208x(-+3=0

We use the square of the difference formula

-208x(-3=0

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