-18+y=6(2-3y)+10=y

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Solution for -18+y=6(2-3y)+10=y equation: 



-18+y=6(2-3y)+10=y

We move all terms to the left:

-18+y-(6(2-3y)+10)=0

We add all the numbers together, and all the variables

y-(6(-3y+2)+10)-18=0



We calculate terms in parentheses: -(6(-3y+2)+10), so:

6(-3y+2)+10

We multiply parentheses

-18y+12+10

We add all the numbers together, and all the variables

-18y+22

Back to the equation:

-(-18y+22)



We get rid of parentheses

y+18y-22-18=0

We add all the numbers together, and all the variables

19y-40=0

We move all terms containing y to the left, all other terms to the right

19y=40

y=40/19

y=2+2/19

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