-18-(3y+2)=2(y-2)+3y

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Solution for -18-(3y+2)=2(y-2)+3y equation:


Simplifying
-18 + -1(3y + 2) = 2(y + -2) + 3y

Reorder the terms:
-18 + -1(2 + 3y) = 2(y + -2) + 3y
-18 + (2 * -1 + 3y * -1) = 2(y + -2) + 3y
-18 + (-2 + -3y) = 2(y + -2) + 3y

Combine like terms: -18 + -2 = -20
-20 + -3y = 2(y + -2) + 3y

Reorder the terms:
-20 + -3y = 2(-2 + y) + 3y
-20 + -3y = (-2 * 2 + y * 2) + 3y
-20 + -3y = (-4 + 2y) + 3y

Combine like terms: 2y + 3y = 5y
-20 + -3y = -4 + 5y

Solving
-20 + -3y = -4 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
-20 + -3y + -5y = -4 + 5y + -5y

Combine like terms: -3y + -5y = -8y
-20 + -8y = -4 + 5y + -5y

Combine like terms: 5y + -5y = 0
-20 + -8y = -4 + 0
-20 + -8y = -4

Add '20' to each side of the equation.
-20 + 20 + -8y = -4 + 20

Combine like terms: -20 + 20 = 0
0 + -8y = -4 + 20
-8y = -4 + 20

Combine like terms: -4 + 20 = 16
-8y = 16

Divide each side by '-8'.
y = -2

Simplifying
y = -2

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