-18-6k=6(1/3k)

Solution for -18-6k=6(1/3k) equation:

-18-6k=6(1/3k)

We move all terms to the left:

-18-6k-(6(1/3k))=0


Domain of the equation: 3k))!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

-6k-(6(+1/3k))-18=0

We multiply all the terms by the denominator


-6k*3k))-(6(-18*3k))+1=0

Wy multiply elements

-18k^2-54k=0

a = -18; b = -54; c = 0;
Δ = b2-4ac
Δ = -542-4·(-18)·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-54}{2*-18}=\frac{0}{-36}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+54}{2*-18}=\frac{108}{-36}
=-3
$