-18/7+3/2x=7/5x

Solution for -18/7+3/2x=7/5x equation:

-18/7+3/2x=7/5x

We move all terms to the left:

-18/7+3/2x-(7/5x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/2x-(+7/5x)-18/7=0

We get rid of parentheses

3/2x-7/5x-18/7=0

We calculate fractions


(-900x^2)/490x^2+735x/490x^2+(-686x)/490x^2=0

We multiply all the terms by the denominator


(-900x^2)+735x+(-686x)=0

We get rid of parentheses

-900x^2+735x-686x=0

We add all the numbers together, and all the variables

-900x^2+49x=0

a = -900; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-900)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-900}=\frac{-98}{-1800}
=49/900
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-900}=\frac{0}{-1800}
=0
$