-18=-8y+2(y-3)

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Solution for -18=-8y+2(y-3) equation: 



-18=-8y+2(y-3)

We move all terms to the left:

-18-(-8y+2(y-3))=0



We calculate terms in parentheses: -(-8y+2(y-3)), so:

-8y+2(y-3)

We multiply parentheses

-8y+2y-6

We add all the numbers together, and all the variables

-6y-6

Back to the equation:

-(-6y-6)



We get rid of parentheses

6y+6-18=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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