-18=3(4y-2)

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Solution for -18=3(4y-2) equation: 



-18=3(4y-2)

We move all terms to the left:

-18-(3(4y-2))=0



We calculate terms in parentheses: -(3(4y-2)), so:

3(4y-2)

We multiply parentheses

12y-6

Back to the equation:

-(12y-6)



We get rid of parentheses

-12y+6-18=0

We add all the numbers together, and all the variables

-12y-12=0

We move all terms containing y to the left, all other terms to the right

-12y=12

y=12/-12

y=-1

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