-18=3(4y-2)

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Solution for -18=3(4y-2) equation:



-18=3(4y-2)
We move all terms to the left:
-18-(3(4y-2))=0
We calculate terms in parentheses: -(3(4y-2)), so:
3(4y-2)
We multiply parentheses
12y-6
Back to the equation:
-(12y-6)
We get rid of parentheses
-12y+6-18=0
We add all the numbers together, and all the variables
-12y-12=0
We move all terms containing y to the left, all other terms to the right
-12y=12
y=12/-12
y=-1

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