-18=5(2-z)+2

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Solution for -18=5(2-z)+2 equation: 



-18=5(2-z)+2

We move all terms to the left:

-18-(5(2-z)+2)=0

We add all the numbers together, and all the variables

-(5(-1z+2)+2)-18=0



We calculate terms in parentheses: -(5(-1z+2)+2), so:

5(-1z+2)+2

We multiply parentheses

-5z+10+2

We add all the numbers together, and all the variables

-5z+12

Back to the equation:

-(-5z+12)



We get rid of parentheses

5z-12-18=0

We add all the numbers together, and all the variables

5z-30=0

We move all terms containing z to the left, all other terms to the right

5z=30

z=30/5

z=6

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