-18=8(y-5)+3y

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Solution for -18=8(y-5)+3y equation: 



-18=8(y-5)+3y

We move all terms to the left:

-18-(8(y-5)+3y)=0



We calculate terms in parentheses: -(8(y-5)+3y), so:

8(y-5)+3y

We add all the numbers together, and all the variables

3y+8(y-5)

We multiply parentheses

3y+8y-40

We add all the numbers together, and all the variables

11y-40

Back to the equation:

-(11y-40)



We get rid of parentheses

-11y+40-18=0

We add all the numbers together, and all the variables

-11y+22=0

We move all terms containing y to the left, all other terms to the right

-11y=-22

y=-22/-11

y=+2

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