-18m(m+2)=0

Solution for -18m(m+2)=0 equation:

-18m(m+2)=0

We multiply parentheses

-18m^2-36m=0

a = -18; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·(-18)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*-18}=\frac{0}{-36}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*-18}=\frac{72}{-36}
=-2
$