-18x+48=3x2

Solution for -18x+48=3x2 equation:

-18x+48=3x^2

We move all terms to the left:

-18x+48-(3x^2)=0

determiningTheFunctionDomain
-3x^2-18x+48=0

a = -3; b = -18; c = +48;
Δ = b2-4ac
Δ = -182-4·(-3)·48
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-30}{2*-3}=\frac{-12}{-6}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+30}{2*-3}=\frac{48}{-6}
=-8
$