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-18x^2-x+5=0
We add all the numbers together, and all the variables
-18x^2-1x+5=0
a = -18; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·(-18)·5
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-19}{2*-18}=\frac{-18}{-36} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+19}{2*-18}=\frac{20}{-36} =-5/9 $
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