-18y-4(10y+13)=-8(4y+13)

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Solution for -18y-4(10y+13)=-8(4y+13) equation: 



-18y-4(10y+13)=-8(4y+13)

We move all terms to the left:

-18y-4(10y+13)-(-8(4y+13))=0

We multiply parentheses

-18y-40y-(-8(4y+13))-52=0



We calculate terms in parentheses: -(-8(4y+13)), so:

-8(4y+13)

We multiply parentheses

-32y-104

Back to the equation:

-(-32y-104)



We add all the numbers together, and all the variables

-58y-(-32y-104)-52=0

We get rid of parentheses

-58y+32y+104-52=0

We add all the numbers together, and all the variables

-26y+52=0

We move all terms containing y to the left, all other terms to the right

-26y=-52

y=-52/-26

y=+2

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