-19(x+2)+6(4x-4)=4(x-4)+8

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Solution for -19(x+2)+6(4x-4)=4(x-4)+8 equation: 



-19(x+2)+6(4x-4)=4(x-4)+8

We move all terms to the left:

-19(x+2)+6(4x-4)-(4(x-4)+8)=0

We multiply parentheses

-19x+24x-(4(x-4)+8)-38-24=0



We calculate terms in parentheses: -(4(x-4)+8), so:

4(x-4)+8

We multiply parentheses

4x-16+8

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

5x-(4x-8)-62=0

We get rid of parentheses

5x-4x+8-62=0

We add all the numbers together, and all the variables

x-54=0

We move all terms containing x to the left, all other terms to the right

x=54

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