-19(z+2)+6(4z-7)=4(z-4)+11

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Solution for -19(z+2)+6(4z-7)=4(z-4)+11 equation: 



-19(z+2)+6(4z-7)=4(z-4)+11

We move all terms to the left:

-19(z+2)+6(4z-7)-(4(z-4)+11)=0

We multiply parentheses

-19z+24z-(4(z-4)+11)-38-42=0



We calculate terms in parentheses: -(4(z-4)+11), so:

4(z-4)+11

We multiply parentheses

4z-16+11

We add all the numbers together, and all the variables

4z-5

Back to the equation:

-(4z-5)



We add all the numbers together, and all the variables

5z-(4z-5)-80=0

We get rid of parentheses

5z-4z+5-80=0

We add all the numbers together, and all the variables

z-75=0

We move all terms containing z to the left, all other terms to the right

z=75

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