-19=3(r+12)-19

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Solution for -19=3(r+12)-19 equation: 



-19=3(r+12)-19

We move all terms to the left:

-19-(3(r+12)-19)=0



We calculate terms in parentheses: -(3(r+12)-19), so:

3(r+12)-19

We multiply parentheses

3r+36-19

We add all the numbers together, and all the variables

3r+17

Back to the equation:

-(3r+17)



We get rid of parentheses

-3r-17-19=0

We add all the numbers together, and all the variables

-3r-36=0

We move all terms containing r to the left, all other terms to the right

-3r=36

r=36/-3

r=-12

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