-19y(y+3)+6(4y-7)=4(y-6)+13

Solution for -19y(y+3)+6(4y-7)=4(y-6)+13 equation:

-19y(y+3)+6(4y-7)=4(y-6)+13

We move all terms to the left:

-19y(y+3)+6(4y-7)-(4(y-6)+13)=0

We multiply parentheses

-19y^2-57y+24y-(4(y-6)+13)-42=0


We calculate terms in parentheses: -(4(y-6)+13), so:

4(y-6)+13

We multiply parentheses

4y-24+13

We add all the numbers together, and all the variables

4y-11

Back to the equation:

-(4y-11)


We add all the numbers together, and all the variables

-19y^2-33y-(4y-11)-42=0

We get rid of parentheses

-19y^2-33y-4y+11-42=0

We add all the numbers together, and all the variables

-19y^2-37y-31=0

a = -19; b = -37; c = -31;
Δ = b2-4ac
Δ = -372-4·(-19)·(-31)
Δ = -987
Delta is less than zero, so there is no solution for the equation