-1=(-6/5)(2)+b

Solution for -1=(-6/5)(2)+b equation:

-1=(-6/5)(2)+b

We move all terms to the left:

-1-((-6/5)(2)+b)=0


Domain of the equation: 5)2+b)!=0

b!=0/1

b!=0

b∈R


We multiply all the terms by the denominator


-((-6-1*5)2+b)=0


We calculate terms in parentheses: -((-6-1*5)2+b), so:

(-6-1*5)2+b

determiningTheFunctionDomain
b+(-6-1*5)2

We add all the numbers together, and all the variables

b+(-11)2

We add all the numbers together, and all the variables

b-22

Back to the equation:

-(b-22)


We get rid of parentheses

-b+22=0

We add all the numbers together, and all the variables

-1b+22=0

We move all terms containing b to the left, all other terms to the right

-b=-22

b=-22/-1

b=+22