-1=-1/2(b+2)+3b

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Solution for -1=-1/2(b+2)+3b equation:



-1=-1/2(b+2)+3b
We move all terms to the left:
-1-(-1/2(b+2)+3b)=0
Domain of the equation: 2(b+2)+3b)!=0
b∈R
We multiply all the terms by the denominator
-(-1-1*2(b+2)+3b)=0
We calculate terms in parentheses: -(-1-1*2(b+2)+3b), so:
-1-1*2(b+2)+3b
determiningTheFunctionDomain -1*2(b+2)+3b-1
We add all the numbers together, and all the variables
3b-1*2(b+2)-1
Wy multiply elements
3b-2b(b-1
Back to the equation:
-(3b-2b(b-1)
We calculate terms in parentheses: -(3b-2b(b-1), so:
3b-2b(b-1
We calculate terms in parentheses: -(3b-2b(b-1), so:
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We calculate terms in parentheses: -(3b-2b(b-1), so:
3b-2b(b-1
We calculate terms in parentheses: -(3b-2b(b-1), so:
3b-2b(b-1
We calculate terms in parentheses: -(3b-2b(b-1), so:
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We calculate terms in parentheses: -(3b-2b(b-1), so:
3b-2b(b-1
We calculate terms in parentheses: -(3b-2b(b-1), so:
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We calculate terms in parentheses: -(3b-2b(b-1), so:
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We calculate terms in parentheses: -(3b-2b(b-1), so:
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We calculate te

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