-1=1/3(-3)+b

Solution for -1=1/3(-3)+b equation:

-1=1/3(-3)+b

We move all terms to the left:

-1-(1/3(-3)+b)=0


Domain of the equation: 3(-3)+b)!=0

b∈R


We multiply all the terms by the denominator


-(1-1*3(-3)+b)=0


We calculate terms in parentheses: -(1-1*3(-3)+b), so:

1-1*3(-3)+b

determiningTheFunctionDomain
b+1-1*3(-3)

We add all the numbers together, and all the variables

b+10

Back to the equation:

-(b+10)


We get rid of parentheses

-b-10=0

We add all the numbers together, and all the variables

-1b-10=0

We move all terms containing b to the left, all other terms to the right

-b=10

b=10/-1

b=-10