-1=3(n-1)+2(1-2n)

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Solution for -1=3(n-1)+2(1-2n) equation: 



-1=3(n-1)+2(1-2n)

We move all terms to the left:

-1-(3(n-1)+2(1-2n))=0

We add all the numbers together, and all the variables

-(3(n-1)+2(-2n+1))-1=0



We calculate terms in parentheses: -(3(n-1)+2(-2n+1)), so:

3(n-1)+2(-2n+1)

We multiply parentheses

3n-4n-3+2

We add all the numbers together, and all the variables

-1n-1

Back to the equation:

-(-1n-1)



We get rid of parentheses

1n+1-1=0

We add all the numbers together, and all the variables

n=0

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