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-1=3(w2)-8w
We move all terms to the left:
-1-(3(w2)-8w)=0
We add all the numbers together, and all the variables
-(+3w^2-8w)-1=0
We get rid of parentheses
-3w^2+8w-1=0
a = -3; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·(-3)·(-1)
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{13}}{2*-3}=\frac{-8-2\sqrt{13}}{-6} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{13}}{2*-3}=\frac{-8+2\sqrt{13}}{-6} $
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