-1q+4(1-q)=2q+(-3)(1-q)

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Solution for -1q+4(1-q)=2q+(-3)(1-q) equation: 



-1q+4(1-q)=2q+(-3)(1-q)

We move all terms to the left:

-1q+4(1-q)-(2q+(-3)(1-q))=0

We add all the numbers together, and all the variables

-1q+4(-1q+1)-(2q+(-3)(-1q+1))=0

We multiply parentheses

-1q-4q-(2q+(-3)(-1q+1))+4=0

We multiply parentheses ..

-1q-4q-(2q+(+3q-3))+4=0



We calculate terms in parentheses: -(2q+(+3q-3)), so:

2q+(+3q-3)

We add all the numbers together, and all the variables

2q+(3q-3)

We get rid of parentheses

2q+3q-3

We add all the numbers together, and all the variables

5q-3

Back to the equation:

-(5q-3)



We add all the numbers together, and all the variables

-5q-(5q-3)+4=0

We get rid of parentheses

-5q-5q+3+4=0

We add all the numbers together, and all the variables

-10q+7=0

We move all terms containing q to the left, all other terms to the right

-10q=-7

q=-7/-10

q=7/10

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