-1x(10x+8)=-10

Solution for -1x(10x+8)=-10 equation:

-1x(10x+8)=-10

We move all terms to the left:

-1x(10x+8)-(-10)=0

We add all the numbers together, and all the variables

-1x(10x+8)+10=0

We multiply parentheses

-10x^2-8x+10=0

a = -10; b = -8; c = +10;
Δ = b2-4ac
Δ = -82-4·(-10)·10
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{29}}{2*-10}=\frac{8-4\sqrt{29}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{29}}{2*-10}=\frac{8+4\sqrt{29}}{-20}
$