-2(-2+4c)=2(-8c-2)

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Solution for -2(-2+4c)=2(-8c-2) equation: 



-2(-2+4c)=2(-8c-2)

We move all terms to the left:

-2(-2+4c)-(2(-8c-2))=0

We add all the numbers together, and all the variables

-2(4c-2)-(2(-8c-2))=0

We multiply parentheses

-8c-(2(-8c-2))+4=0



We calculate terms in parentheses: -(2(-8c-2)), so:

2(-8c-2)

We multiply parentheses

-16c-4

Back to the equation:

-(-16c-4)



We get rid of parentheses

-8c+16c+4+4=0

We add all the numbers together, and all the variables

8c+8=0

We move all terms containing c to the left, all other terms to the right

8c=-8

c=-8/8

c=-1

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