-2(-2x+1)=2-(3-x)-4=0

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Solution for -2(-2x+1)=2-(3-x)-4=0 equation: 



-2(-2x+1)=2-(3-x)-4=0

We move all terms to the left:

-2(-2x+1)-(2-(3-x)-4)=0

We add all the numbers together, and all the variables

-2(-2x+1)-(2-(-1x+3)-4)=0

We multiply parentheses

4x-(2-(-1x+3)-4)-2=0



We calculate terms in parentheses: -(2-(-1x+3)-4), so:

2-(-1x+3)-4

determiningTheFunctionDomain
-(-1x+3)+2-4

We add all the numbers together, and all the variables

-(-1x+3)-2

We get rid of parentheses

1x-3-2

We add all the numbers together, and all the variables

x-5

Back to the equation:

-(x-5)



We get rid of parentheses

4x-x+5-2=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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