-2(-2y+4)-8y=2(y-2)-2

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Solution for -2(-2y+4)-8y=2(y-2)-2 equation: 



-2(-2y+4)-8y=2(y-2)-2

We move all terms to the left:

-2(-2y+4)-8y-(2(y-2)-2)=0

We add all the numbers together, and all the variables

-8y-2(-2y+4)-(2(y-2)-2)=0

We multiply parentheses

-8y+4y-(2(y-2)-2)-8=0



We calculate terms in parentheses: -(2(y-2)-2), so:

2(y-2)-2

We multiply parentheses

2y-4-2

We add all the numbers together, and all the variables

2y-6

Back to the equation:

-(2y-6)



We add all the numbers together, and all the variables

-4y-(2y-6)-8=0

We get rid of parentheses

-4y-2y+6-8=0

We add all the numbers together, and all the variables

-6y-2=0

We move all terms containing y to the left, all other terms to the right

-6y=2

y=2/-6

y=-1/3

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