-2(-3k+7)=3(3k-2)+k

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Solution for -2(-3k+7)=3(3k-2)+k equation: 



-2(-3k+7)=3(3k-2)+k

We move all terms to the left:

-2(-3k+7)-(3(3k-2)+k)=0

We multiply parentheses

6k-(3(3k-2)+k)-14=0



We calculate terms in parentheses: -(3(3k-2)+k), so:

3(3k-2)+k

We add all the numbers together, and all the variables

k+3(3k-2)

We multiply parentheses

k+9k-6

We add all the numbers together, and all the variables

10k-6

Back to the equation:

-(10k-6)



We get rid of parentheses

6k-10k+6-14=0

We add all the numbers together, and all the variables

-4k-8=0

We move all terms containing k to the left, all other terms to the right

-4k=8

k=8/-4

k=-2

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