-2(-3y-2)=-25y+3-2)+2(1+5y)

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Solution for -2(-3y-2)=-25y+3-2)+2(1+5y) equation: 



-2(-3y-2)=-25y+3-2)+2(1+5y)

We move all terms to the left:

-2(-3y-2)-(-25y+3-2)+2(1+5y))=0

We add all the numbers together, and all the variables

-2(-3y-2)-(-25y+1)+2(5y+1))=0

We multiply parentheses

6y-(-25y+1)+10y+4+=0

We get rid of parentheses

6y+25y+10y-1+4+=0

We add all the numbers together, and all the variables

41y=0

y=0/41

y=0

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