-2(-3y-25)2y=22

Solution for -2(-3y-25)2y=22 equation:

-2(-3y-25)2y=22

We move all terms to the left:

-2(-3y-25)2y-(22)=0

We multiply parentheses

12y^2+100y-22=0

a = 12; b = 100; c = -22;
Δ = b2-4ac
Δ = 1002-4·12·(-22)
Δ = 11056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11056}=\sqrt{16*691}=\sqrt{16}*\sqrt{691}=4\sqrt{691}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{691}}{2*12}=\frac{-100-4\sqrt{691}}{24}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{691}}{2*12}=\frac{-100+4\sqrt{691}}{24}
$