-2(-3z-5)-12=-6(-1z+5)+27

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Solution for -2(-3z-5)-12=-6(-1z+5)+27 equation:



-2(-3z-5)-12=-6(-1z+5)+27
We move all terms to the left:
-2(-3z-5)-12-(-6(-1z+5)+27)=0
We multiply parentheses
6z-(-6(-1z+5)+27)+10-12=0
We calculate terms in parentheses: -(-6(-1z+5)+27), so:
-6(-1z+5)+27
We multiply parentheses
6z-30+27
We add all the numbers together, and all the variables
6z-3
Back to the equation:
-(6z-3)
We add all the numbers together, and all the variables
6z-(6z-3)-2=0
We get rid of parentheses
6z-6z+3-2=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation

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