-2(-3z-5)-12=-6(-1z+5)+27

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Solution for -2(-3z-5)-12=-6(-1z+5)+27 equation: 



-2(-3z-5)-12=-6(-1z+5)+27

We move all terms to the left:

-2(-3z-5)-12-(-6(-1z+5)+27)=0

We multiply parentheses

6z-(-6(-1z+5)+27)+10-12=0



We calculate terms in parentheses: -(-6(-1z+5)+27), so:

-6(-1z+5)+27

We multiply parentheses

6z-30+27

We add all the numbers together, and all the variables

6z-3

Back to the equation:

-(6z-3)



We add all the numbers together, and all the variables

6z-(6z-3)-2=0

We get rid of parentheses

6z-6z+3-2=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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