-2(-6u+2)-3u=3(u-1)-9

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Solution for -2(-6u+2)-3u=3(u-1)-9 equation: 



-2(-6u+2)-3u=3(u-1)-9

We move all terms to the left:

-2(-6u+2)-3u-(3(u-1)-9)=0

We add all the numbers together, and all the variables

-3u-2(-6u+2)-(3(u-1)-9)=0

We multiply parentheses

-3u+12u-(3(u-1)-9)-4=0



We calculate terms in parentheses: -(3(u-1)-9), so:

3(u-1)-9

We multiply parentheses

3u-3-9

We add all the numbers together, and all the variables

3u-12

Back to the equation:

-(3u-12)



We add all the numbers together, and all the variables

9u-(3u-12)-4=0

We get rid of parentheses

9u-3u+12-4=0

We add all the numbers together, and all the variables

6u+8=0

We move all terms containing u to the left, all other terms to the right

6u=-8

u=-8/6

u=-1+1/3

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