-2(-6y+5)-3y=3(y-5)-5

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Solution for -2(-6y+5)-3y=3(y-5)-5 equation:



-2(-6y+5)-3y=3(y-5)-5
We move all terms to the left:
-2(-6y+5)-3y-(3(y-5)-5)=0
We add all the numbers together, and all the variables
-3y-2(-6y+5)-(3(y-5)-5)=0
We multiply parentheses
-3y+12y-(3(y-5)-5)-10=0
We calculate terms in parentheses: -(3(y-5)-5), so:
3(y-5)-5
We multiply parentheses
3y-15-5
We add all the numbers together, and all the variables
3y-20
Back to the equation:
-(3y-20)
We add all the numbers together, and all the variables
9y-(3y-20)-10=0
We get rid of parentheses
9y-3y+20-10=0
We add all the numbers together, and all the variables
6y+10=0
We move all terms containing y to the left, all other terms to the right
6y=-10
y=-10/6
y=-1+2/3

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