-2(-7x+2)-8x=2(x-4)-2

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Solution for -2(-7x+2)-8x=2(x-4)-2 equation: 



-2(-7x+2)-8x=2(x-4)-2

We move all terms to the left:

-2(-7x+2)-8x-(2(x-4)-2)=0

We add all the numbers together, and all the variables

-8x-2(-7x+2)-(2(x-4)-2)=0

We multiply parentheses

-8x+14x-(2(x-4)-2)-4=0



We calculate terms in parentheses: -(2(x-4)-2), so:

2(x-4)-2

We multiply parentheses

2x-8-2

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

6x-(2x-10)-4=0

We get rid of parentheses

6x-2x+10-4=0

We add all the numbers together, and all the variables

4x+6=0

We move all terms containing x to the left, all other terms to the right

4x=-6

x=-6/4

x=-1+1/2

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