-2(-8v+4)4v=2(v-4)-6

Solution for -2(-8v+4)4v=2(v-4)-6 equation:

-2(-8v+4)4v=2(v-4)-6

We move all terms to the left:

-2(-8v+4)4v-(2(v-4)-6)=0

We multiply parentheses

64v^2-32v-(2(v-4)-6)=0


We calculate terms in parentheses: -(2(v-4)-6), so:

2(v-4)-6

We multiply parentheses

2v-8-6

We add all the numbers together, and all the variables

2v-14

Back to the equation:

-(2v-14)


We get rid of parentheses

64v^2-32v-2v+14=0

We add all the numbers together, and all the variables

64v^2-34v+14=0

a = 64; b = -34; c = +14;
Δ = b2-4ac
Δ = -342-4·64·14
Δ = -2428
Delta is less than zero, so there is no solution for the equation