-2(-9y+3)-3y=3(y-2)-2

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Solution for -2(-9y+3)-3y=3(y-2)-2 equation: 



-2(-9y+3)-3y=3(y-2)-2

We move all terms to the left:

-2(-9y+3)-3y-(3(y-2)-2)=0

We add all the numbers together, and all the variables

-3y-2(-9y+3)-(3(y-2)-2)=0

We multiply parentheses

-3y+18y-(3(y-2)-2)-6=0



We calculate terms in parentheses: -(3(y-2)-2), so:

3(y-2)-2

We multiply parentheses

3y-6-2

We add all the numbers together, and all the variables

3y-8

Back to the equation:

-(3y-8)



We add all the numbers together, and all the variables

15y-(3y-8)-6=0

We get rid of parentheses

15y-3y+8-6=0

We add all the numbers together, and all the variables

12y+2=0

We move all terms containing y to the left, all other terms to the right

12y=-2

y=-2/12

y=-1/6

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